What is Fermi level pinning?

What is Fermi level pinning?

Abstract: Fermi level pinning refers to a situation where the band bending in a semiconductor contacting a metal is essentially independent of the metal even for large variation in the work function of the metal.

What is Fermi level position?

(a) Fermi level position in pure semiconductors (18) is of the order of 1 eV, while the second is of the order of a few tens of millielectron volts at 300 K. Consequently, we see from this equation that the Fermi level should typically lie very close to the middle of the energy gap in intrinsic semiconductors.

What is Fermi level diagram?

The term Fermi level is mainly used in discussing the solid state physics of electrons in semiconductors, and a precise usage of this term is necessary to describe band diagrams in devices comprising different materials with different levels of doping.

Why Fermi level is so important?

It is important in determining the electrical and thermal properties of solids. The value of the Fermi level at absolute zero (−273.15 °C) is called the Fermi energy and is a constant for each solid. The Fermi level changes as the solid is warmed and as electrons are added to or withdrawn from the solid.

What is the theory of Fermi level pinning?

Abstract: Fermi-level pinning of poly-Si and metal-silicide gate materials on Hf-based gate dielectrics has been systematically studied theoretically. Fermi-level pinning in high-work-function materials is governed by the O vacancy generation and subsequent formation of interface dipoles near gate electrodes due to the electron transfer.

Why does the Fermi level always get stuck?

It doesn’t matter how lightly or how heavily doped your semiconductor, your Fermi level will always get stuck at that energy level. That phenomenon is called the Fermi level pinning and it takes away a very very important degree of freedom for engineering for semiconductor devices.

How does the Fermi level affect the behavior of semiconductors?

Any deviation from this level will result in some charge on the surface. But, in equilibrium, the Fermi level must be a constant throughout the semiconductor. This means that the semiconductor bands must bend at the surface in much the same way that they bend at a pn junction. GaAs suffers from extreme Fermi-level pinning (silicon does not).

Why does GaAs suffer from extreme Fermi level pinning?

But, in equilibrium, the Fermi level must be a constant throughout the semiconductor. This means that the semiconductor bands must bend at the surface in much the same way that they bend at a pn junction. GaAs suffers from extreme Fermi-level pinning (silicon does not).

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