What is the coordination number of NaCl?
In NaCl crystal, each sodium ion is surrounded by 6 chloride ions and each chloride ion is surrounded by 6 sodium ions. So, the coordination number of NaCl as per definition will be 6:6.
Is NaCl BCC or FCC?
General Notes. NaCl has a cubic unit cell. It is best thought of as a face-centered cubic array of anions with an interpenetrating fcc cation lattice (or vice-versa). The cell looks the same whether you start with anions or cations on the corners.
What is the coordination number of body centered cubic?
Body centered cubic structure (CsCl structure). The coordination number of the unit cell is eight.
How do you find the Z value of NaCl?
The cations occupy the void positions (octahedral, tetrahedral, cubic voids respectively). In this way, in NaCl structure, we get 4 CL(-) and 4 Na(+) per unit cell. And Z effective in this case becomes the total number of ‘formula’ units per cell which we say is 4.
What does a cubic unit cell in NaCl look like?
General Notes NaCl has a cubic unit cell. It is best thought of as a face-centered cubic array of anions with an interpenetrating fcc cation lattice (or vice-versa). The cell looks the same whether you start with anions or cations on the corners.
How many packing atoms are in a NaCl cell?
The NaCl structure is a good example of the latter. One octahedral and one tetrahedral site in a face-centered cubic unit cell. Each cell contains four packing atoms (gray), four octahedral sites (pink), and eight tetrahedral sites (blue).
What is the CN of a body centered cubic crystal?
Body-Centered Cubic Coordination Number. Coordination Number (CN) is the number of nearest neighbors that each atom has. In a body-centered cubic crystal, each atom has 8 nearest neighbors (NN). That is not the maximum (which is 12, found in close-packed structures), but BCC has such high stability because of its next-nearest neighbors.
How is NaCl composed of FCC and Na + units?
NaCl is composed by the Na+ FCC unit cell plus the displace Cl– FCC unit cell, thus the calculation of is similar to the pure FCC case and becomes the following :
